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Carboxylic Acid Derivatives: Reactivity Order and Nucleophilic Acyl Substitution
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Carboxylic acid derivatives are compounds in which the OH of a carboxylic acid is replaced by another group: a halide (acid chloride), a carboxylate (anhydride), an alkoxy group (ester) or an amine (amide). They share one reaction type, nucleophilic acyl substitution, and one ranking of reactivity.
Reactivity order
Acid chloride > anhydride > ester (about equal to carboxylic acid) > amide
Reactivity tracks how good the leaving group is and how electrophilic the carbonyl carbon is.
| Derivative | Leaving group | Why |
|---|---|---|
| Acid chloride | Cl- | Excellent leaving group (conjugate base of a strong acid); Cl withdraws electrons and does little resonance donation |
| Anhydride | Carboxylate | Good leaving group, stabilized by resonance |
| Ester | Alkoxide | Poorer leaving group; oxygen donates some electron density to the carbonyl |
| Amide | Amide ion | Very poor leaving group; nitrogen lone pair donates strongly into the carbonyl by resonance |
The resonance point explains why amides are the least reactive and why peptide bonds are stable enough to build proteins, as discussed in the protein structure note. Leaving group quality follows the same acid strength logic as the pKa note: weaker base means better leaving group.
The mechanism: addition, then elimination
Unlike SN2, this is a two-step process through a tetrahedral intermediate.
- Addition. The nucleophile attacks the carbonyl carbon. The C=O pi bond breaks and the oxygen becomes negative, giving a tetrahedral intermediate. The carbon changes from sp2 to sp3.
- Elimination. The C=O reforms and the leaving group departs.
The net result is that the leaving group is swapped for the nucleophile. Compare this with the single-step backside attack in the SN1/SN2 note. Acyl substitution occurs at a planar carbonyl carbon, so there is no backside inversion.
Interconversion rule
You can convert a more reactive derivative into a less reactive one directly, but not the reverse without extra activation.
- Acid chloride + alcohol gives an ester.
- Acid chloride + amine gives an amide.
- Anhydride + amine gives an amide plus a carboxylic acid.
- Ester + amine can give an amide, but slowly.
- Amide to ester or acid usually needs harsh conditions such as strong acid or base and heat.
Hydrolysis
Hydrolysis gives the carboxylic acid (or carboxylate in base) and the leaving group. Base-promoted ester hydrolysis is called saponification. It is effectively irreversible because the carboxylate product is deprotonated and no longer electrophilic. Acid-catalyzed ester hydrolysis is reversible, and Le Chatelier's principle controls the yield.
Spotting them by IR
The C=O stretch sits at different positions: acid chlorides near 1800 cm-1, anhydrides show two peaks near 1800 and 1750, esters near 1735, and amides lower, about 1650, because of resonance. The IR and NMR note covers the method.
Common traps
- Reversing the reactivity order. Amides are the least reactive.
- Calling it SN2. It goes through a tetrahedral intermediate, not a single concerted step.
- Forgetting the nucleophile must be able to displace a worse leaving group.
One-minute recap
Acid chloride > anhydride > ester > amide, set by leaving group ability and resonance donation. Nucleophilic acyl substitution is addition to the carbonyl followed by elimination of the leaving group, and reactive derivatives convert easily into less reactive ones.
Check yourself: 5-question mini-quiz
1. Which is more reactive toward nucleophiles, an ester or an amide, and why?
The ester. In an amide the nitrogen lone pair donates strongly by resonance and the amide ion is a poor leaving group.
2. What is the intermediate in nucleophilic acyl substitution?
A tetrahedral intermediate, formed when the nucleophile adds to the carbonyl carbon.
3. Why is saponification irreversible?
The carboxylic acid product is deprotonated by base to a carboxylate, which is not electrophilic enough to be attacked by the alcohol.
4. Can an ester be converted into an acid chloride by simple treatment with chloride ion?
No. Chloride is a weaker nucleophile and a better leaving group than alkoxide, so the reaction goes the wrong way.
5. Which carboxylic acid derivative shows a C=O stretch at the lowest wavenumber, about 1650 cm-1?
The amide, because nitrogen resonance donation weakens the C=O bond.
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Keep studying
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