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How to Calculate Map Units From Recombination Frequency
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A map unit (1 centimorgan, cM) is 1 percent recombination between two genes. To convert, count recombinant offspring, divide by total offspring, and multiply by 100; the result in percent is the distance in map units. That is all the arithmetic. The work is in picking out which offspring are recombinants.
The method
- Find the parental classes. They are the two most common phenotypes from a test cross.
- Everything else is recombinant. Add up the counts in the other classes.
- Divide by the total number of offspring, including parentals.
- Multiply by 100. The percent equals map units.
- Add distances for adjacent intervals. Distances between neighboring genes add up along a chromosome.
Worked problem 1: two genes
A test cross gives 420 AB, 410 ab, 90 Ab and 80 aB, out of 1,000 offspring.
- Parentals: AB and ab (830).
- Recombinants: Ab and aB (170).
- 170 / 1,000 = 0.17, so 17 percent, or 17 map units.
Worked problem 2: from a percent
Genes X and Y show 8 percent recombination. In 2,500 offspring, how many are recombinants?
- 8 percent of 2,500 = 200 recombinants, split roughly equally between the two recombinant classes.
Worked problem 3: three genes in a line
Three genes are tested pairwise: A to B is 10 map units, B to C is 6 map units, A to C is 16 map units.
- The largest distance is between the outer genes, so B is in the middle: A to B to C.
- Check: 10 + 6 = 16. The distances add.
Why it tops out at 50 percent
Even genes very far apart, or on different chromosomes, give at most 50 percent recombinants in a test cross. Multiple crossovers can undo each other, so large raw distances underestimate the true distance. Long maps are built by adding short intervals.
Common traps
- Counting parentals as recombinants. The largest two classes are parental.
- Using only one recombinant class. Add both.
- Dividing by the parental count. Divide by the total.
- Expecting more than 50 percent. Observed values stay at or below 50 percent.
One-minute recap
- Recombinants / total x 100 = percent = map units.
- Largest two classes are parental.
- Largest pairwise distance spans the outer genes.
Check yourself: 5-question mini-quiz
1. How many map units is 12 percent recombination?
12 map units (12 cM).
2. In a test cross, how do you identify the parental classes?
They are the two most common phenotype classes.
3. A test cross has 150 recombinants out of 1,500 offspring. What is the map distance?
150 / 1,500 = 10 percent, so 10 map units.
4. If A to B is 7 and B to C is 5 map units, what is A to C if B is in the middle?
12 map units.
5. What is the maximum recombination frequency seen in a test cross?
50 percent.
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