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Pure vs Mixed Noncompetitive Inhibition: Km, Vmax and Lineweaver-Burk
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Noncompetitive inhibitors bind away from the active site, so they can bind the free enzyme (E) or the enzyme-substrate complex (ES). Pure and mixed differ in whether the inhibitor binds E and ES equally well.
Comparison
| Binding | Vmax | Km | Lineweaver-Burk lines intersect | |
|---|---|---|---|---|
| Pure noncompetitive | Equal affinity for E and ES | Decreases | Unchanged | On the x-axis |
| Mixed | Different affinity for E and ES | Decreases | Increases or decreases | Left of the y-axis, off the x-axis |
The Vmax drop happens in both because some enzyme is effectively removed from catalysis, and adding substrate does not rescue it.
Why Km differs
- Pure: the inhibitor binds E and ES equally, so it does not change how well substrate binds. Km is unchanged.
- Mixed, prefers E: substrate binding is hindered, so apparent Km increases.
- Mixed, prefers ES: substrate binding is favored, so apparent Km decreases.
Many textbooks and the MCAT use "noncompetitive" for the pure case. Mixed inhibition is a general case; competitive and uncompetitive are its limiting forms.
Compared with other types
- Competitive: binds E only. Km up, Vmax unchanged, lines meet on the y-axis.
- Uncompetitive: binds ES only. Km and Vmax both down, parallel lines.
Common traps
- Thinking more substrate overcomes noncompetitive inhibition. It does not.
- Saying Km changes in pure noncompetitive inhibition.
- Forgetting that Lineweaver-Burk uses reciprocals. The x-intercept is -1/Km.
One-minute recap
- Pure: Vmax down, Km same.
- Mixed: Vmax down, Km shifts either way.
- Both bind away from the active site.
Check yourself: 5-question mini-quiz
1. What happens to Vmax in pure noncompetitive inhibition?
It decreases.
2. What happens to Km in pure noncompetitive inhibition?
It is unchanged.
3. How does mixed inhibition differ from pure?
The inhibitor has different affinities for E and ES, so Km changes.
4. Where do pure noncompetitive Lineweaver-Burk lines intersect?
On the x-axis.
5. Does more substrate overcome noncompetitive inhibition?
No.
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