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Why Freezing Point Depression Is a Colligative Property

By StudyStore · Published 2026-11-09 · 1 min read · 186 words

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Freezing point depression is colligative because it depends only on how many solute particles are dissolved, not on what they are. A solute dilutes the solvent, which makes the liquid more stable relative to the pure solid, so the solution must be cooled further to freeze.

The formula

ΔTf = i · Kf · m

  • i: van't Hoff factor, the number of particles per formula unit.
  • Kf: solvent constant.
  • m: molality, mol solute per kg solvent.

The freezing point falls by ΔTf from the pure solvent value.

Particle count, not identity

  • 1 m glucose: i = 1.
  • 1 m NaCl: i near 2.
  • 1 m CaCl2: i near 3, so the largest drop.

Why molality

Molality does not change with temperature, unlike molarity, so it is used for freezing point and boiling point problems.

Common traps

  • Forgetting i for ionic compounds.
  • Using molarity instead of molality.
  • Raising instead of lowering. Boiling point goes up; freezing point goes down.
  • Thinking the solute freezes out. In ideal cases pure solvent freezes first.

Check yourself: 5-question mini-quiz

Try each question first, then click it to reveal the answer.

1. Why is freezing point depression colligative?

It depends on the number of dissolved particles, not their identity.

2. Which gives the larger drop, 1 m NaCl or 1 m glucose?

NaCl, since i is about 2.

3. Why use molality?

It does not change with temperature.

4. What is i for CaCl2?

About 3.

5. What happens to boiling point with a solute?

It rises.

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Written by StudyStore from standard scientific facts. Study aid only. Always check values against the reference your exam provides.

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