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Why Freezing Point Depression Is a Colligative Property
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Freezing point depression is colligative because it depends only on how many solute particles are dissolved, not on what they are. A solute dilutes the solvent, which makes the liquid more stable relative to the pure solid, so the solution must be cooled further to freeze.
The formula
ΔTf = i · Kf · m
- i: van't Hoff factor, the number of particles per formula unit.
- Kf: solvent constant.
- m: molality, mol solute per kg solvent.
The freezing point falls by ΔTf from the pure solvent value.
Particle count, not identity
- 1 m glucose: i = 1.
- 1 m NaCl: i near 2.
- 1 m CaCl2: i near 3, so the largest drop.
Why molality
Molality does not change with temperature, unlike molarity, so it is used for freezing point and boiling point problems.
Common traps
- Forgetting i for ionic compounds.
- Using molarity instead of molality.
- Raising instead of lowering. Boiling point goes up; freezing point goes down.
- Thinking the solute freezes out. In ideal cases pure solvent freezes first.
Check yourself: 5-question mini-quiz
1. Why is freezing point depression colligative?
It depends on the number of dissolved particles, not their identity.
2. Which gives the larger drop, 1 m NaCl or 1 m glucose?
NaCl, since i is about 2.
3. Why use molality?
It does not change with temperature.
4. What is i for CaCl2?
About 3.
5. What happens to boiling point with a solute?
It rises.
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Keep studying
- Colligative Properties: Freezing Point Depression Calculations
- Osmotic Pressure and the van't Hoff Factor: Colligative Properties Calculations
- Ksp: Solubility Product, Q vs Ksp and the Common Ion Effect
- Calorimetry: Specific Heat, Latent Heat and Phase Change Calculations
- Infrared Spectroscopy for the MCAT: Functional Group Peaks Table
- Half-Equivalence Point vs Equivalence Point: What Is the Difference?
- What Delta G = 0 Means: Equilibrium, Q vs K and Delta G Standard
- All free notes
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