StudyStore

MCAT 4A · Chem/Phys

Motion, Forces, Work and Energy

490 original Anki flashcards, an 11-page illustrated study guide, a 4-page cheat sheet and 47 practice questions for MCAT content category 4A.

What is inside

  • deck.apkg490 original Anki flashcards (256 short answer, 109 multiple choice, 46 cloze, 70 true/false, 9 image occlusion), 22 original diagrams
  • guide.pdf11-page illustrated study guide that explains the ideas
  • cheatsheet.pdf4 printable pages, US Letter at 100 percent
  • questions.pdf47 original MCAT-style practice questions with explanations, including 3 passage-based sets
  • README.txtimport steps
  • 256 short answer
  • 109 multiple choice
  • 46 cloze
  • 70 true/false
  • 9 image occlusion

Topics (21)

  • 01UnUnits, dimensional analysis and significant figures
  • 02VeVectors and scalars
  • 03DiDisplacement, velocity and acceleration
  • 04KiKinematic equations
  • 05FrFree fall and projectile motion
  • 06NeNewton's laws
  • 07GrGravity and weight
  • 08FrFriction
  • 09InInclined planes
  • 10CiCircular motion and centripetal force
  • 11ToTorque and rotational equilibrium
  • 12TrTranslational equilibrium
  • 13WoWork
  • 14KiKinetic energy and the work-energy theorem
  • 15PoPotential energy (gravitational and elastic)
  • 16CoConservation of mechanical energy
  • 17PoPower
  • 18SiSimple machines and mechanical advantage
  • 19MoMomentum and impulse
  • 20ElElastic and inelastic collisions
  • 21CeCenter of mass

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Previews

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Sample card (answer side)
Sample card (answer side)
Sample card (answer side)
Sample card (answer side)
Cheat sheet, page 1 (partial preview)
Cheat sheet, page 2 (partial preview)
Study guide, page 1 (partial preview)
Study guide, page 2 (partial preview)

Try it · sample practice questions

Five questions from the pack.

0 of 5 answered

Q1A sprinter runs at 36 km/h. Her speed in m/s is

A. Divide km/h by 3.6: 36/3.6 = 10 m/s. Multiplying by 3.6 gives 129.6, the common inversion error. The speed is not unchanged in m/s, and 1.0 is off by a factor of ten.

Q2A projectile is launched at 40 m/s at 60 degrees above level ground. Its speed at the highest point is

B. Only the horizontal component remains at the peak: 40 cos 60 = 20 m/s. Zero is the vertical component there, 34.6 is the initial vertical component, and 40 is the launch speed.

Q3A 0.40 kg ball on a 0.80 m string moves in a horizontal circle at 4.0 m/s. The tension is

A. T = m v^2/r = 0.40 x 16/0.80 = 8.0 N. The value 2.0 N forgets to square the speed (mv/r), 6.4 N forgets to divide by the radius, and 20 N is the acceleration v^2/r with the mass left out.

Q4A spring with k = 300 N/m is stretched 0.20 m from equilibrium. The stored energy is

D. U = 1/2 k x^2 = 0.5 x 300 x 0.04 = 6.0 J. The value 12 J forgets the 1/2, 60 J mistakes the spring force kx = 60 N for an energy, and 3.0 J halves again.

Q5A crowbar has an effort arm of 1.2 m and a load arm of 0.20 m. Ideally, an effort of 50 N lifts a load of

D. Ideal MA = 1.2/0.20 = 6, so the load is 6 x 50 = 300 N. The value 8.3 N divides by the arm ratio instead of multiplying, 250 N uses a ratio of 5, and 60 N uses a ratio of 1.2.

Those are real questions from the pack, word for word.

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