MCAT 4C · Chem/Phys
Electrostatics, Circuits, Magnetism and Electrochemistry
396 original Anki flashcards, an 8-page illustrated study guide, a 3-page cheat sheet and 57 practice questions for MCAT content category 4C.
What is inside
- deck.apkg396 original Anki flashcards (101 short answer, 118 multiple choice, 108 cloze, 61 true/false, 8 image occlusion), 28 original diagrams
- guide.pdf8-page illustrated study guide that explains the ideas
- cheatsheet.pdf3 printable pages, US Letter at 100 percent
- questions.pdf57 original MCAT-style practice questions with explanations, including 4 passage-based sets
- README.txtimport steps
- 101 short answer
- 118 multiple choice
- 108 cloze
- 61 true/false
- 8 image occlusion
Topics (26)
- 01ChCharge and Coulomb's law
- 02ElElectric field and field lines
- 03ElElectric potential and potential energy
- 04EqEquipotential surfaces
- 05ElElectric dipoles
- 06CuCurrent, resistance and resistivity
- 07OhOhm's law
- 08SeSeries and parallel resistors
- 09KiKirchhoff's laws
- 10PoPower in circuits
- 11CaCapacitance and dielectrics
- 12CaCapacitors in series and parallel
- 13RcRC circuits
- 14AlAlternating current basics and rms
- 15MeMeters: ammeter and voltmeter
- 16MaMagnetic fields and sources
- 17MaMagnetic force on charges and currents (right-hand rule)
- 18ElElectromagnetic induction basics
- 19GaGalvanic cells
- 20ElElectrolytic cells
- 21StStandard reduction potentials and cell EMF
- 22FrFree energy and cell potential
- 23NeNernst equation and concentration cells
- 24BaBatteries and rechargeable cells
- 25ElElectrolysis and Faraday's law
- 26BiBiological applications: nerve conduction, ECG
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Try it · sample practice questions
Five questions from the pack.
Q1Two point charges exert a force F on each other. One charge is tripled and the separation is halved. The new force is:
D. Tripling one charge multiplies F by 3, and halving r multiplies it by 4 (inverse square), so F becomes 12F. 6F misses the square on r, 3F/4 puts the factor on the wrong side, and 3F/2 mixes the two errors.
Q2A battery with an open-circuit voltage of 9.0 V delivers 2.0 A with a terminal voltage of 6.0 V. What is its internal resistance?
B. The lost voltage is 9.0 - 6.0 = 3.0 V across r, so r = 3.0 V/2.0 A = 1.5 ohm. 3.0 ohm is the external resistance (6.0/2.0), 4.5 ohm would be 9.0/2.0 (the total resistance), and 0.67 ohm inverts the ratio.
Q3A 2.0 uF capacitor discharges through a 1.0 megohm resistor. About how long does it take for the voltage to fall to half its starting value?
D. tau = RC = 2.0 s and the half-time is tau ln 2 = 0.693 x 2.0 = 1.4 s. 2.0 s is the time to reach 37 percent, 0.50 s inverts tau, and 4.0 s is 2 tau (13.5 percent left).
Q4A 0.20 m wire carrying 4.0 A is perpendicular to a 0.30 T field. The magnetic force on the wire is:
B. F = BIL sin 90 = (0.30)(4.0)(0.20) = 0.24 N. 0.060 N is B x L x 1 (forgetting the current), 0.015 N is a misplaced decimal, and 3.8 N inverts the arithmetic.
Q5Three metals have standard reduction potentials A+/A = +0.50 V, B2+/B = -0.20 V, and C+/C = -1.00 V. Which pair gives a galvanic cell with the largest E0 cell?
D. The largest E0 comes from the most negative anode and the most positive cathode: 0.50 - (-1.00) = 1.50 V with C as the anode and A as the cathode. The 0.70 V and 0.80 V pairs are galvanic but smaller, and the last pair reverses the roles, giving a negative (nonspontaneous) value.
Those are real questions from the pack, word for word.